-4h^2+20h-25=0

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Solution for -4h^2+20h-25=0 equation: 



-4h^2+20h-25=0

a = -4; b = 20; c = -25;
Δ = b2-4ac
Δ = 202-4·(-4)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{-20}{-8}=2+1/2$

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